1800 United States presidential election in Kentucky

The 1800 United States presidential election in Kentucky took place between 31 October and 3 December 1800, as part of the 1800 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

1800 United States presidential election in Kentucky
← 1796 31 October – 11 December 1800 1804 →
 
Nominee Thomas Jefferson John Adams
Party Democratic-Republican Federalist
Home state Virginia Massachusetts
Running mate Aaron Burr Charles C. Pinckney
Electoral vote 4 0
Popular vote 119 0
Percentage 100.00% 0.00%

Kentucky cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into two electoral districts with two electors each, whereupon each district's voters chose the electors.[2]

Results

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1800 United States presidential election in Kentucky[3]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Thomas Jefferson 119 100.00% 4
Federalist John Adams (incumbent) 0 0.00% 0
Totals 119 100.00% 4

See also

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References

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  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 14, 2023.
  2. ^ "1800 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  3. ^ "1800 Presidential Election". 270towin.com. Retrieved July 14, 2023.