Jump to content

1993 Virginia Slims of Houston – Doubles

From Wikipedia, the free encyclopedia

Doubles
1993 Virginia Slims of Houston
Final
Champions
Runners-up
Score6–3, 5–7, 7–6(9–7)
Details
Draw16 (1Q/1LL)
Seeds4
Events
Singles Doubles
← 1992 · Virginia Slims of Houston · 1994 →

Patty Fendick and Mary Joe Fernández were the defending champions, but none competed this year.

Katrina Adams and Manon Bollegraf won the title by defeating Eugenia Maniokova and Radka Zrubáková 6–3, 5–7, 7–6(9–7) in the final.[1]

Seeds

[edit]

Draw

[edit]

Key

[edit]

Draw

[edit]
First round Quarterfinals Semifinals Final
1 United States K Adams
Netherlands M Bollegraf
6 77
Q 2 60 1 United States K Adams
Netherlands M Bollegraf
6 6
Austria P Ritter
Netherlands C Vis
6 77 1 3
1 61 1 United States K Adams
Netherlands M Bollegraf
6 6
4 United Kingdom J Durie
New Zealand J Richardson
61 6 6 2 2
77 3 2 4 3 0
2 66 Bulgaria K Maleeva
Switzerland M Maleeva-Fragnière
6 6
Bulgaria K Maleeva
Switzerland M Maleeva-Fragnière
6 78 1 United States K Adams
Netherlands M Bollegraf
6 5 79
Russia E Maniokova
Slovakia R Zrubáková
6 6 3 7 67
WC United States Kellie Dorman-Tyrone
Republic of Ireland Philippa Palmer
1 1 Russia E Maniokova
Slovakia R Zrubáková
6 2 79
3 2 3 4 6 67
3 Germany K Kschwendt
Argentina F Labat
6 6 Russia E Maniokova
Slovakia R Zrubáková
6 6
Netherlands I Driehuis
Mexico L Novelo
6 3 6 2 4 4
4 6 2 3 63
65 3 2 Italy S Cecchini
Argentina P Tarabini
6 77
2 Italy S Cecchini
Argentina P Tarabini
77 6

References

[edit]
  1. ^ "Tennis WTA Houston Doubles 1993 Scores". Tennis 24. Retrieved June 29, 2023.
[edit]