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1962 Wimbledon Championships – Girls' singles

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Girls' singles
1962 Wimbledon Championships
Final
ChampionSoviet Union Galina Baksheeva
Runner-upNew Zealand Elizabeth Terry
Score6–4, 6–2
Details
Draw18
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1961 · Wimbledon Championships · 1963 →

Galina Baksheeva successfully defended her title, defeating Elizabeth Terry in the final, 6–4, 6–2 to win the girls' singles tennis title at the 1962 Wimbledon Championships.[1]

Draw

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Key

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Finals

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Semifinals Final
          
Soviet Union Galina Baksheeva 6 6
Denmark Birgit Grage 4 1
Soviet Union Galina Baksheeva 6 6
New Zealand Elizabeth Terry 4 2
New Zealand Elizabeth Terry 6 7 6
United Kingdom Sally Holdsworth 2 9 4

Top half

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First round Second round Quarterfinals Semifinals
Finland Christina Lindström 2 1
Netherlands Anja Lepoutre 6 6
Netherlands A Lepoutre 8 1 1
Soviet Union G Baksheeva 6 6 6
Soviet Union Galina Baksheeva 6 6
Brazil L Fineberg 1 2
Soviet Union G Baksheeva 6 6
Denmark B Grage 4 1
Indonesia Lita Liem w/o
Poland D Makulska
Poland D Makulska 6 1
Denmark B Grage 8 6
Austria R Leyrer 3 4
Sweden E Hultkrantz 4 3 Denmark B Grage 6 6
Denmark Birgit Grage 6 6

Bottom half

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First round Second round Quarterfinals Semifinals
Republic of Ireland A Keegan 2 4
New Zealand Elizabeth Terry 6 6 New Zealand E Terry 6 6
France Françoise Courteix 4 2
New Zealand E Terry 6 6
Belgium O Jacob 1 3
Belgium O Jacob 8 6
Switzerland I Gubler 6 1
New Zealand E Terry 6 7 6
United Kingdom S Holdsworth 2 9 4
British Guiana J Franker 1 1
United Kingdom Sally Holdsworth 6 6
United Kingdom S Holdsworth 6 8
Norway K Robsahm 3 6
Norway Kirsten Robsahm 2 6 6
Mexico C Hawley 6 4 4

References

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  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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