2015 Apia International Sydney – Men's doubles
Appearance
This article needs additional citations for verification. (February 2024) |
Men's doubles | |
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2015 Apia International Sydney | |
Champions | |
Runners-up | |
Score | 6–4, 7–6(7–5) |
Daniel Nestor and Nenad Zimonjić were the defending champions, but chose not to participate together. Nestor plays alongside Rohan Bopanna. Zimonjić teamed up with Aisam-ul-Haq Qureshi, but lost in the quarterfinals to Robert Lindstedt and Marcin Matkowski.
Rohan Bopanna and Daniel Nestor won the title.[1]
Seeds
[edit]Julien Benneteau /
Édouard Roger-Vasselin (semifinals)
Jean-Julien Rojer /
Horia Tecău (final)
Rohan Bopanna /
Daniel Nestor (champions)
Aisam-ul-Haq Qureshi /
Nenad Zimonjić (quarterfinals)
Draw
[edit]Key
[edit]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals
[edit]First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
4 | 2 | 1 | 77 | 3 | [10] | ||||||||||||||||||||||
4 | 6 | [4] | 61 | 6 | [5] | ||||||||||||||||||||||
6 | 4 | [10] | 1 | 6 | 3 | [3] | |||||||||||||||||||||
3 | 611 | 7 | [10] | 3 | 2 | 6 | [10] | ||||||||||||||||||||
713 | 5 | [6] | 3 | 7 | 6 | ||||||||||||||||||||||
6 | 7 | 5 | 3 | ||||||||||||||||||||||||
4 | 5 | 3 | 6 | 77 | |||||||||||||||||||||||
WC | 2 | 4 | 65 | ||||||||||||||||||||||||
w/o | 6 | 6 | |||||||||||||||||||||||||
4 | 4 | 4 | 4 | 3 | |||||||||||||||||||||||
4 | 6 | 6 | 3 | 6 | [8] | ||||||||||||||||||||||
4 | 69 | 2 | 6 | 3 | [10] | ||||||||||||||||||||||
6 | 711 | 2 | 3 | ||||||||||||||||||||||||
WC | 2 | 67 | 2 | 6 | 6 | ||||||||||||||||||||||
2 | 6 | 79 |
References
[edit]- ^ "Rohan Bopanna-Daniel Nestor Win Sydney International". NDTV Sports. 17 January 2015. Retrieved 19 February 2024.